IndietroSolving for the Indicated Variable – College Algebra Practice
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Q7. Solve for x: \( \frac{x}{a} - bx = c \)
Background
Topic: Solving Linear Equations for a Variable
This question tests your ability to manipulate algebraic equations to isolate a specific variable, a fundamental skill in College Algebra.
Key Terms and Formulas:
Linear equation: An equation involving variables to the first power.
Isolate: To get the variable alone on one side of the equation.
Step-by-Step Guidance
Start by identifying all terms containing \( x \) and move them to one side of the equation.
Factor \( x \) out of the terms where possible to simplify the equation.
Express the equation so that \( x \) is multiplied by a single coefficient.
Set up the equation to solve for \( x \) by dividing both sides by the coefficient of \( x \).
Try solving on your own before revealing the answer!
Final Answer: \( x = \frac{a c}{1 + a b} \)
After combining like terms and factoring, you isolate \( x \) and solve by dividing both sides by the coefficient.
Q8. Solve for L: \( S = 2LW + 2LH + 2HW \)
Background
Topic: Solving Formulas for a Variable
This question tests your ability to rearrange a formula to solve for a specific variable, which is a common skill in College Algebra and applied mathematics.
Key Terms and Formulas:
Formula: An equation that relates multiple variables.
Isolate: To get the variable alone on one side of the equation.
Step-by-Step Guidance
Identify all terms containing \( L \) in the equation.
Group the terms with \( L \) together on one side of the equation.
Factor \( L \) out of the grouped terms.
Set up the equation so that \( L \) is multiplied by a single expression, then prepare to solve for \( L \).
Try solving on your own before revealing the answer!
Final Answer: \( L = \frac{S - 2HW}{2(W + H)} \)
By grouping and factoring, you isolate \( L \) and solve by dividing both sides by the coefficient.
Q9. Solve for c: \( \frac{1}{a} + \frac{1}{b} - \frac{1}{c} = d \)
Background
Topic: Solving Rational Equations for a Variable
This question tests your ability to manipulate rational equations and solve for a variable in the denominator, a key skill in College Algebra.
Key Terms and Formulas:
Rational equation: An equation involving fractions with variables in the denominator.
Isolate: To get the variable alone on one side of the equation.
Step-by-Step Guidance
Move the \( \frac{1}{c} \) term to one side of the equation and all other terms to the opposite side.
Express the equation so that \( \frac{1}{c} \) is isolated.
Take the reciprocal of both sides to solve for \( c \).
Set up the final expression for \( c \) in terms of the other variables.
Try solving on your own before revealing the answer!
Final Answer: \( c = \frac{1}{\frac{1}{a} + \frac{1}{b} - d} \)
By isolating \( \frac{1}{c} \) and taking the reciprocal, you solve for \( c \) in terms of the other variables.