write-a-balanced-chemical-equation-for-the-reaction-of-boron-trifluoride-bf3-gas

Question

Write a balanced chemical equation for the reaction of boron trifluoride (BF_{3}) gas with water to form boric acid ($$H_{3}BO$$_{3}) and hydrogen fluoride (HF).

Accepted Answer

BF_{3}(g) + 3 $$H_{2}O(l$$) → $$H_{3}BO$$_{3}(aq) + 3 HF(g)

Answer

2 BF_{3}(g) + 6 $$H_{2}O(l$$) → 2 $$H_{3}BO$$_{3}(aq) + 6 HF(g)

Answer

BF_{3}(g) + 2 $$H_{2}O(l$$) → 2 $$H_{3}BO$$_{3}(aq) + 6 HF(aq)

Answer

3 BF_{3}(g) + 9 $$H_{2}O(l$$) → 3 $$H_{3}BO$$_{3}(aq) + 9 HF(aq)

Write a balanced chemical equation for the reaction of boron trifluoride (BF3) gas with water to form boric acid (H3BO3) and hydrogen fluoride (HF).

Write a balanced chemical equation for the reaction of boron trifluoride (BF₃) gas with water to form boric acid (H₃BO₃) and hydrogen fluoride (HF).