find-the-kinetic-energy-of-1-00-mole-of-the-following-noble-gases-at-25-c-he-ne-

Question

Find the kinetic energy of 1.00 mole of the following noble gases at 25 °C: He, Ne, and Ar.

Accepted Answer

KE of He = KE of Ne = KE of Ar = 3.72×$$10^{3} J$$

Answer

KE of He = KE of Ne = KE of Ar = 3.72×$$10^{3} kJ$$

Answer

KE of He = KE of Ne = KE of Ar = 3.67×$$10^{1} J$$

Answer

cannot be determined since masses of the gases are not given