IndietroGeneral Chemistry II: Thermodynamics, Equilibrium, and Kinetics Practice Exam Guidance
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Q1. Consider a reaction that has a positive ΔH and a negative ΔS. Which of the following statements is TRUE?
Background
Topic: Thermodynamics – Spontaneity of Reactions
This question tests your understanding of how enthalpy (ΔH) and entropy (ΔS) changes affect the spontaneity of a reaction, using the Gibbs free energy equation.
Key Terms and Formulas
ΔH: Change in enthalpy (heat content)
ΔS: Change in entropy (disorder)
ΔG: Change in Gibbs free energy
Key formula:
Step-by-Step Guidance
Recall that a reaction is spontaneous when .
Analyze the signs: Here, (endothermic) and (decrease in disorder).
Plug these signs into the Gibbs free energy equation: .
Consider how temperature affects with these signs.
Try solving on your own before revealing the answer!
Final Answer: C) This reaction will be nonspontaneous at all temperatures.
With and , will always be positive, regardless of temperature, so the reaction is never spontaneous.
Q2. Calculate ΔS°rxn for the following reaction: N2H4(l) + H2(g) → 2 NH3(g). S° (J/mol·K): N2H4(l) = 121.2, H2(g) = 130.7, NH3(g) = 192.8
Background
Topic: Entropy Change in Chemical Reactions
This question tests your ability to calculate the standard entropy change for a reaction using standard molar entropy values.
Key Terms and Formulas
ΔS°rxn: Standard entropy change of reaction
S°: Standard molar entropy
Key formula:
Step-by-Step Guidance
Write the balanced equation: N2H4(l) + H2(g) → 2 NH3(g).
List the S° values for each species and their coefficients.
Calculate the total S° for products: J/mol·K.
Calculate the total S° for reactants: J/mol·K.
Set up the formula: .
Try solving on your own before revealing the answer!
Final Answer: A) +133.7 J/K
J/K
Q3. The ________ Law of Thermodynamics states that for any spontaneous reaction, the entropy of the universe increases.
Background
Topic: Laws of Thermodynamics
This question tests your knowledge of the Second Law of Thermodynamics and its statement about entropy and spontaneity.
Key Terms
Entropy (S): A measure of disorder or randomness.
Second Law of Thermodynamics: The entropy of the universe increases for any spontaneous process.
Step-by-Step Guidance
Recall the statements of the four main laws of thermodynamics.
Identify which law specifically addresses entropy and spontaneity.
Match the law to the statement in the question.
Try solving on your own before revealing the answer!
Final Answer: C) Second
The Second Law of Thermodynamics states that the entropy of the universe increases for any spontaneous process.
Q4. Calculate the ΔG°rxn using the following information: 2 HNO3(aq) + NO(g) → 3 NO2(g) + H2O(l). ΔG°f (kJ/mol): HNO3(aq) = -110.9, NO(g) = 87.6, NO2(g) = 51.3, H2O(l) = -237.1
Background
Topic: Standard Gibbs Free Energy Change of Reaction
This question tests your ability to calculate the standard Gibbs free energy change for a reaction using standard free energies of formation.
Key Terms and Formulas
ΔG°rxn: Standard Gibbs free energy change of reaction
ΔG°f: Standard Gibbs free energy of formation
Key formula:
Step-by-Step Guidance
Write the balanced equation and identify the coefficients for each species.
Multiply each ΔG°f value by its coefficient in the balanced equation.
Sum the ΔG°f values for the products and for the reactants separately.
Set up the formula: .
Try solving on your own before revealing the answer!
Final Answer: B) +51.0 kJ
Plugging in the values and performing the arithmetic gives ΔG°rxn = +51.0 kJ.
Q5. Determine the equilibrium constant for the following reaction at 298 K: SO3(g) + H2O(g) → H2SO4(l), ΔG° = -90.5 kJ
Background
Topic: Relationship Between ΔG° and Equilibrium Constant (K)
This question tests your ability to relate the standard Gibbs free energy change to the equilibrium constant using the appropriate thermodynamic equation.
Key Terms and Formulas
ΔG°: Standard Gibbs free energy change
K: Equilibrium constant
R: Gas constant (8.314 J/mol·K)
T: Temperature in Kelvin
Key formula:
Step-by-Step Guidance
Convert ΔG° from kJ to J (multiply by 1000).
Plug in the values for ΔG°, R, and T into the equation .
Rearrange the equation to solve for K: .
Set up the calculation for the exponent: .
Try solving on your own before revealing the answer!
Final Answer: A) 7.31 × 1015
After converting units and plugging in the values, the equilibrium constant K is approximately 7.31 × 1015.
Q6. Use Hess's law to calculate ΔG°rxn for CO(g) → C(s) + 1/2 O2(g) given: CO2(g) → C(s) + O2(g), ΔG°rxn = +394.4 kJ; CO(g) + 1/2 O2(g) → CO2(g), ΔG°rxn = -257.2 kJ
Background
Topic: Hess's Law for Gibbs Free Energy
This question tests your ability to use Hess's Law to combine reactions and their ΔG° values to find the ΔG° for a target reaction.
Key Terms and Formulas
Hess's Law: The total ΔG° for a reaction is the sum of ΔG° values for individual steps that add up to the overall reaction.
Step-by-Step Guidance
Write out all given reactions and their ΔG° values.
Manipulate (reverse or multiply) the given reactions as needed so that when added, they yield the target reaction.
Remember to reverse the sign of ΔG° if you reverse a reaction.
Add the ΔG° values for the manipulated reactions to get the total ΔG° for the target reaction.
Try solving on your own before revealing the answer!
Final Answer: D) +137.2 kJ
By reversing and adding the given reactions appropriately, the ΔG°rxn for CO(g) → C(s) + 1/2 O2(g) is +137.2 kJ.