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General Chemistry Study Guide: Key Concepts and Practice Problems

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Q1. Define and provide an example for each of the following: atom, element, molecule, compound.

Background

Topic: Basic Chemical Terminology

This question tests your understanding of fundamental chemical concepts and the ability to distinguish between atoms, elements, molecules, and compounds.

Key Terms:

  • Atom: The smallest unit of an element that retains its chemical properties.

  • Element: A substance made up of only one type of atom.

  • Molecule: Two or more atoms bonded together.

  • Compound: A substance formed when two or more different elements are chemically bonded.

Step-by-Step Guidance

  1. Start by defining each term clearly and concisely.

  2. Think of a simple example for each term (e.g., atom: hydrogen atom, element: oxygen, molecule: O2, compound: H2O).

  3. Write out the examples and explain why they fit the definition.

Try solving on your own before revealing the answer!

Final Answer:

  • Atom: Hydrogen atom (H)

  • Element: Oxygen (O)

  • Molecule: O2 (two oxygen atoms bonded together)

  • Compound: H2O (water, made of hydrogen and oxygen)

Each example illustrates the definition provided.

Q2. Name the following organic compound: CH3CH2CH2COOH

Background

Topic: Organic Nomenclature

This question tests your ability to apply IUPAC rules to name organic compounds, specifically carboxylic acids.

Key Terms:

  • Carboxylic acid: Organic compound containing a -COOH group.

  • IUPAC naming: Systematic method for naming organic molecules.

Step-by-Step Guidance

  1. Identify the longest carbon chain containing the carboxylic acid group.

  2. Count the number of carbons in the chain.

  3. Apply the correct suffix for carboxylic acids (-oic acid).

  4. Combine the root name with the suffix to form the compound's name.

Try solving on your own before revealing the answer!

Final Answer: Butanoic acid

The compound has four carbons and a carboxylic acid group, so its name is butanoic acid.

Q3. Calculate the mass in grams of 7.10 × 10-4 mol SO2 molecules.

Background

Topic: Mole Calculations and Mass

This question tests your ability to convert moles to grams using molar mass.

Key formula:

$\text{mass (g)} = \text{moles} \times \text{molar mass (g/mol)}$

Key Terms:

  • Mole: Unit for amount of substance.

  • Molar mass: Mass of one mole of a substance.

Step-by-Step Guidance

  1. Find the molar mass of SO2 (S = 32.07 g/mol, O = 16.00 g/mol).

  2. Calculate the total molar mass: $32.07 + 2 \times 16.00$.

  3. Multiply the number of moles by the molar mass to get the mass in grams.

Try solving on your own before revealing the answer!

Final Answer: 0.079 g SO2

$\text{mass} = 7.10 \times 10^{-4} \times 64.07 = 0.079 \text{ g}$

We used the correct molar mass and multiplied by the number of moles.

Q4. The grams of carbon in 7.10 × 10-4 mol sodium hydrogen carbonate, NaHCO3.

Background

Topic: Mole Calculations and Elemental Composition

This question tests your ability to find the mass of a specific element in a compound given the number of moles.

Key formula:

$\text{mass of element} = \text{moles} \times \text{atomic mass of element}$

Key Terms:

  • Atomic mass: Mass of one mole of an element.

  • Mole: Unit for amount of substance.

Step-by-Step Guidance

  1. Identify the number of carbon atoms per formula unit of NaHCO3 (there is one).

  2. Find the atomic mass of carbon (12.01 g/mol).

  3. Multiply the number of moles by the atomic mass to get the mass of carbon.

Try solving on your own before revealing the answer!

Final Answer: 0.0085 g C

$\text{mass} = 7.10 \times 10^{-4} \times 12.01 = 0.0085 \text{ g}$

We multiplied the moles by the atomic mass of carbon.

Q5. The number of hydrogen atoms in 1.2 g of (NH4)2SO4.

Background

Topic: Mole Calculations and Counting Atoms

This question tests your ability to use molar mass and Avogadro's number to find the number of atoms in a sample.

Key formula:

$\text{Number of atoms} = \text{moles} \times \text{Avogadro's number} \times \text{number of H atoms per formula unit}$

Key Terms:

  • Avogadro's number: $6.022 \times 10^{23}$ atoms/mol

  • Molar mass: Mass of one mole of a compound

Step-by-Step Guidance

  1. Calculate the molar mass of (NH4)2SO4.

  2. Find the number of moles in 1.2 g by dividing by the molar mass.

  3. Determine the number of hydrogen atoms per formula unit (8).

  4. Multiply the moles by Avogadro's number and by 8 to get the total number of hydrogen atoms.

Try solving on your own before revealing the answer!

Final Answer: 1.28 × 1023 atoms

We calculated the moles, then multiplied by Avogadro's number and the number of H atoms per formula unit.

Q6. Write a balanced chemical equation, including state functions, for the reaction: Gaseous carbon monoxide reacts with hydrogen gas to form gaseous methane (CH4) and liquid water.

Background

Topic: Chemical Equations and Balancing

This question tests your ability to write and balance chemical equations, including physical states.

Key Terms:

  • Balanced equation: Reactants and products have equal numbers of each atom.

  • State functions: Indicate physical state (s, l, g, aq).

Step-by-Step Guidance

  1. Write the formulas for all reactants and products, including their states.

  2. Count the number of atoms of each element on both sides.

  3. Adjust coefficients to balance the equation.

  4. Check that all atoms and charges are balanced.

Try solving on your own before revealing the answer!

Final Answer:

$\text{CO(g) + 3H}_2\text{(g) } \rightarrow \text{ CH}_4\text{(g) + H}_2\text{O(l)}$

The equation is balanced and includes state functions.

Q7. Zn(s) reacts with nitric acid with oxygen according to the reaction: 2Zn(s) + 2HNO3(aq) + O2(g) → 2Zn(NO3)2(aq) + 2H2O(l). A reaction mixture contains 4.5 g Zn and 2.0 g HNO3. Once the reaction has occurred, which reactant is left over and how much of it remains?

Background

Topic: Limiting Reactant and Stoichiometry

This question tests your ability to identify the limiting reactant and calculate the amount of excess reactant remaining.

Key formula:

$\text{moles} = \frac{\text{mass}}{\text{molar mass}}$

$\text{Use stoichiometric ratios from the balanced equation}$

Key Terms:

  • Limiting reactant: The reactant that is completely consumed first.

  • Excess reactant: The reactant left over after the reaction.

Step-by-Step Guidance

  1. Calculate the moles of Zn and HNO3 using their molar masses.

  2. Use the stoichiometric ratios to determine which reactant is limiting.

  3. Calculate how much of the excess reactant remains after the reaction.

Try solving on your own before revealing the answer!

Final Answer:

HNO3 is the excess reactant, and 0.79 g remains after the reaction.

We used stoichiometry to determine the limiting reactant and calculated the leftover amount.

Q8. Find the mass of Fe2O3 formed when 1.5 g Fe reacts with excess O2 according to: 4Fe + 3O2 → 2Fe2O3.

Background

Topic: Stoichiometry and Mass Calculations

This question tests your ability to use stoichiometry to calculate product mass from a given reactant mass.

Key formula:

$\text{moles} = \frac{\text{mass}}{\text{molar mass}}$

$\text{Use stoichiometric ratios to find moles of product}$

$\text{mass of product} = \text{moles} \times \text{molar mass}$

Key Terms:

  • Stoichiometry: Calculating quantities in chemical reactions.

  • Molar mass: Mass of one mole of a substance.

Step-by-Step Guidance

  1. Calculate the moles of Fe using its molar mass.

  2. Use the balanced equation to find the mole ratio between Fe and Fe2O3.

  3. Calculate the moles of Fe2O3 produced.

  4. Multiply by the molar mass of Fe2O3 to find the mass.

Try solving on your own before revealing the answer!

Final Answer: 2.14 g Fe2O3

We used stoichiometry and molar mass to calculate the mass of product formed.

Q9. Give the oxidation number of manganese in the following: (a) MnO2 (b) KMnO4

Background

Topic: Oxidation Numbers

This question tests your ability to assign oxidation numbers to elements in compounds.

Key Terms:

  • Oxidation number: The charge an atom would have if all bonds were ionic.

Step-by-Step Guidance

  1. Assign oxidation numbers to oxygen (-2) and potassium (+1).

  2. Set up equations for the sum of oxidation numbers in each compound.

  3. Solve for the oxidation number of manganese in each case.

Try solving on your own before revealing the answer!

Final Answer:

  • (a) MnO2: +4

  • (b) KMnO4: +7

We used the rules for assigning oxidation numbers.

Q10. Identify the oxidizing and reducing agents in the following redox reaction: MnO4- + Fe2+ → Mn2+ + Fe3+

Background

Topic: Redox Reactions

This question tests your ability to identify oxidizing and reducing agents in a redox reaction.

Key Terms:

  • Oxidizing agent: Causes oxidation, is reduced.

  • Reducing agent: Causes reduction, is oxidized.

Step-by-Step Guidance

  1. Assign oxidation numbers to Mn and Fe in reactants and products.

  2. Determine which element is oxidized and which is reduced.

  3. Identify the oxidizing and reducing agents based on these changes.

Try solving on your own before revealing the answer!

Final Answer:

  • Oxidizing agent: MnO4-

  • Reducing agent: Fe2+

MnO4- is reduced, Fe2+ is oxidized.

Q11. Complete the following reactions with balanced molecular, total ionic, and net ionic equations. Identify the precipitate in each reaction.

Background

Topic: Ionic Equations and Precipitation Reactions

This question tests your ability to write molecular, total ionic, and net ionic equations, and to identify precipitates.

Key Terms:

  • Molecular equation: Shows all reactants and products as compounds.

  • Total ionic equation: Shows all soluble ionic substances as ions.

  • Net ionic equation: Shows only the species that change during the reaction.

  • Precipitate: Insoluble product formed in a reaction.

Step-by-Step Guidance

  1. Write the balanced molecular equation for each reaction.

  2. Break all soluble compounds into ions for the total ionic equation.

  3. Cancel spectator ions to write the net ionic equation.

  4. Use solubility rules to identify the precipitate.

Try solving on your own before revealing the answer!

Final Answer:

Each reaction has a balanced molecular, total ionic, and net ionic equation. The precipitate is the insoluble product (e.g., BaSO4, Mg(OH)2, AgCl, etc.).

Refer to solubility rules to identify the precipitate in each case.

Q12. Give the systematic names for the formulas, or the formulas for the names, for the following compounds.

Background

Topic: Nomenclature of Inorganic Compounds

This question tests your ability to name inorganic compounds and write formulas from names.

Key Terms:

  • Systematic name: IUPAC name for a compound.

  • Formula: Chemical representation of a compound.

Step-by-Step Guidance

  1. For each formula, apply IUPAC rules to name the compound.

  2. For each name, write the correct chemical formula.

  3. Check for polyatomic ions and oxidation states as needed.

Try solving on your own before revealing the answer!

Final Answer:

  • ClC6H13O2N: Chlorohexanamide

  • H2SO4: Sulfuric acid

  • Na2SO3: Sodium sulfite

  • Al2S3: Aluminum sulfide

  • HClO4: Perchloric acid

  • Al2(SO4)3: Aluminum sulfate

  • H2CO3: Carbonic acid

  • Al2S3: Aluminum sulfide

  • H2SO4: Sulfuric acid

  • HClO4: Perchloric acid

Names and formulas are matched according to IUPAC rules.

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