Question 1

A weather balloon is released at ground level where the pressure is 1.00 atm and the temperature is 300 K. The balloon has a volume of 2.00 L. As it rises to a higher altitude, the pressure drops to 0.80 atm and the temperature decreases to 270 K. What is the new volume of the balloon? Use the combined gas law: $$\frac{P_1V_1}{T_1$} = \frac{P_2V_2}{T_2$}.$$

Accepted Answer

$$V_2 = 2.22$$\ \mathrm{L}$$

Question 2

Which of the following best explains why a weather balloon expands as it rises through the atmosphere, using the ideal gas law $$PV = nRT$$?

Accepted Answer

As atmospheric pressure decreases with altitude, the volume of the balloon increases if the amount of gas and temperature remain constant.

Question 3

A weather balloon contains 5.00 L of gas at 1.00 atm and 273 K. If the balloon rises to a region where the pressure is 0.50 atm and the temperature is 223 K, what will be the new volume? Use $$\frac{P_1V_1}{T_1$} = \frac{P_2V_2}{T_2$}.$$

Accepted Answer

$$V_2 = 6.13$$\ \mathrm{L}$$

Question 4

If a weather balloon is filled with helium at a pressure of 1.20 atm and a temperature of 298 K, and the balloon's volume is 3.00 L, what would the volume be if the balloon rises to a region where the pressure is 0.90 atm and the temperature is 250 K? Use $$\frac{P_1V_1}{T_1$} = \frac{P_2V_2}{T_2$}.$$

Accepted Answer

$$V_2 = 3.18$$\ \mathrm{L}$$

Question 5

A weather balloon is released at sea level (1.00 atm, 293 K) with a volume of 4.00 L. At a higher altitude, the pressure is 0.60 atm and the temperature is 253 K. What is the new volume of the balloon? Use $$\frac{P_1V_1}{T_1$} = \frac{P_2V_2}{T_2$}.$$

Accepted Answer

$$V_2 = 7.75$$\ \mathrm{L}$$

Question 6

Which of the following statements about the combined gas law is correct?

Accepted Answer

It relates pressure, volume, and temperature for a fixed amount of gas.

Question 7

A weather balloon is filled with 2.00 L of gas at 1.00 atm and 273 K. If the balloon rises and the pressure drops to 0.75 atm while the temperature increases to 300 K, what is the new volume? Use $$\frac{P_1V_1}{T_1$} = \frac{P_2V_2}{T_2$}.$$

Accepted Answer

$$V_2 = 2.93$$\ \mathrm{L}$$

Question 8

If the temperature of a weather balloon remains constant as it rises and the pressure decreases, what happens to the volume of the balloon according to Boyle's Law ($$P_1V_1 = P_2V_2$$)?

Accepted Answer

The volume increases.

Question 9

A weather balloon is filled with 10.0 L of gas at 1.00 atm and 273 K. If the balloon rises to a region where the pressure is 0.50 atm and the temperature is 273 K, what is the new volume? Use $$P_1V_1 = P_2V_2.$$

Accepted Answer

$$V_2 = 20.0$$\ \mathrm{L}$$

Question 10

Which of the following is a real-world consequence of not accounting for the expansion of a weather balloon as it rises?

Accepted Answer

The balloon may burst due to excessive internal pressure.

Question 11

A weather balloon is filled with 3.00 L of gas at 1.00 atm and 273 K. If the balloon rises to a region where the pressure is 0.60 atm and the temperature is 243 K, what is the new volume? Use $$\frac{P_1V_1}{T_1$} = \frac{P_2V_2}{T_2$}.$$

Accepted Answer

$$V_2 = 5.61$$\ \mathrm{L}$$

Question 12

Which equation would you use to solve for the final volume of a gas sample when both pressure and temperature change, but the amount of gas remains constant?

Accepted Answer

$$\frac{P_1V_1}{T_1$} = \frac{P_2V_2}{T_2$}$$

Question 13

A weather balloon is filled with 8.00 L of gas at 1.00 atm and 300 K. If the balloon rises to a region where the pressure is 0.70 atm and the temperature is 250 K, what is the new volume? Use $$\frac{P_1V_1}{T_1$} = \frac{P_2V_2}{T_2$}.$$

Accepted Answer

$$V_2 = 13.71$$\ \mathrm{L}$$

Question 14

If a weather balloon is released at a temperature of 273 K and a pressure of 1.00 atm with a volume of 5.00 L, and it rises to a region where the pressure is 0.80 atm and the temperature is 250 K, what is the new volume? Use $$\frac{P_1V_1}{T_1$} = \frac{P_2V_2}{T_2$}.$$

Accepted Answer

$$V_2 = 5.47$$\ \mathrm{L}$$

Gases and the Ideal Gas Law: Pressure and Volume Changes in the Atmosphere

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