Question 1

A weather balloon is released at ground level where the pressure is 1.00 atm and the temperature is 300 K. The balloon has a volume of 2.00 L. As it rises to a higher altitude, the pressure drops to 0.80 atm and the temperature decreases to 270 K. What is the new volume of the balloon? Use the combined gas law: $$\frac{P_1V_1}{T_1$} = \frac{P_2V_2}{T_2$}.$$

Accepted Answer

$$V_2 = 2.22$$\ \mathrm{L}$$

Question 2

Which of the following best explains why a weather balloon expands as it rises through the atmosphere, according to the ideal gas law $$PV = nRT$$?

Accepted Answer

The external pressure decreases, so the volume increases to maintain the relationship in the ideal gas law.

Question 3

A weather balloon is filled with 5.00 L of helium at 1.00 atm and 298 K. If the balloon rises to a region where the pressure is 0.60 atm and the temperature is 250 K, what will be the new volume of the balloon? Use $$\frac{P_1V_1}{T_1$} = \frac{P_2V_2}{T_2$}.$$

Accepted Answer

$$V_2 = 9.93$$\ \mathrm{L}$$

Question 4

If a weather balloon is released at sea level (1.00 atm, 293 K) with a volume of 3.00 L, and it rises to a point where the pressure is 0.50 atm and the temperature is 253 K, what is the final volume? Use $$\frac{P_1V_1}{T_1$} = \frac{P_2V_2}{T_2$}.$$

Accepted Answer

$$V_2 = 6.95$$\ \mathrm{L}$$

Question 5

Which of the following statements about the combined gas law is correct?

Accepted Answer

It relates pressure, volume, and temperature for a fixed amount of gas.

Question 6

A weather balloon is filled at a temperature of 273 K and a pressure of 1.20 atm to a volume of 4.00 L. If the balloon rises to a region where the pressure is 0.90 atm and the temperature is 223 K, what is the new volume? Use $$\frac{P_1V_1}{T_1$} = \frac{P_2V_2}{T_2$}.$$

Accepted Answer

$$V_2 = 3.27$$\ \mathrm{L}$$

Question 7

If the temperature of a weather balloon remains constant as it rises and the pressure decreases, what happens to the volume of the balloon according to Boyle's Law ($$P_1V_1 = P_2V_2$$)?

Accepted Answer

The volume increases.

Question 8

A weather balloon is filled with 2.00 L of gas at 1.00 atm and 273 K. If the balloon rises and the pressure drops to 0.50 atm while the temperature remains constant, what is the new volume?

Accepted Answer

$$V_2 = 4.00$$\ \mathrm{L}$$

Question 9

Which variable must remain constant for the combined gas law $$\frac{P_1V_1}{T_1$} = \frac{P_2V_2}{T_2$} to be $$valid?

Accepted Answer

The number of moles of gas ($$n)$$

Question 10

A weather balloon is filled with 10.0 L of gas at 1.00 atm and 300 K. If the balloon rises to a region where the pressure is 0.70 atm and the temperature is 250 K, what is the new volume? Use $$\frac{P_1V_1}{T_1$} = \frac{P_2V_2}{T_2$}.$$

Accepted Answer

$$V_2 = 8.57$$\ \mathrm{L}$$

Question 11

Which of the following is a real-world application of the combined gas law?

Accepted Answer

Predicting how a weather balloon's volume changes as it rises through the atmosphere.

Question 12

A weather balloon is filled with 6.00 L of gas at 1.00 atm and 273 K. If the balloon rises and the pressure drops to 0.75 atm while the temperature increases to 300 K, what is the new volume? Use $$\frac{P_1V_1}{T_1$} = \frac{P_2V_2}{T_2$}.$$

Accepted Answer

$$V_2 = 8.79$$\ \mathrm{L}$$

Gases: The Ideal Gas Law and Atmospheric Applications

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