Domanda del libro di testo
What do the results of parts (a) and (b) imply about the hemiacetal structure of fructose?
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Ch. 23 - Carbohydrates and Nucleic Acids
Wade9th EditionOrganic ChemistryISBN: 9780135213728
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TOC.tableOfContents
- Ch.1 - Structure and Bonding107
- Ch. 2 - Acids and Bases; Functional Groups115
- Ch.3 - Structure and Stereochemistry of Alkanes100
- Ch.4 - The Study of Chemical Reactions99
- Ch.5 - Stereochemistry93
- Ch.6 - Alkyl Halides; Nucleophilic Substitution118
- Ch. 7 - Structure and Synthesis of Alkenes; Elimination158
- Ch.8 - Reactions of Alkenes171
- Ch.9 - Alkynes91
- Ch.10 - Structure and Synthesis of Alcohols143
- Ch.11 - Reactions of Alcohols104
- Ch. 12 - Infrared Spectroscopy and Mass Spectrometry22
- Ch. 13 - Nuclear Magnetic Resonance Spectroscopy45
- Ch. 14 - Ethers, Epoxides, and Thioethers72
- Ch. 15 - Conjugated Systems, Orbital Symmetry, and Ultraviolet Spectroscopy89
- Ch. 16 - Aromatic Compounds74
- Ch. 17 - Reactions of Aromatic Compounds126
- Ch. 18 - Ketones and Aldehydes193
- Ch. 19 - Amines129
- Ch. 20 - Carboxylic Acids77
- Ch. 21 - Carboxylic Acid Derivatives141
- Ch. 22 - Condensations and Alpha Substitutions of Carbonyl Compounds175
- Ch. 23 - Carbohydrates and Nucleic Acids93
- Ch. 24 - Amino Acids, Peptides, and Proteins54
Capitolo 23, Problema 25a
Show the product that results when fructose is treated with an excess of methyl iodide and silver oxide.
Guida verificata passo dopo passo1
Identify the functional groups in fructose: Fructose is a monosaccharide with a ketone group (ketose) and multiple hydroxyl (-OH) groups. These hydroxyl groups are reactive and can undergo methylation.
Understand the role of methyl iodide (CH3I) and silver oxide (Ag2O): Methyl iodide is a methylating agent, and silver oxide acts as a base to facilitate the reaction. Together, they replace the hydrogen atoms of hydroxyl groups with methyl groups (-CH3).
Determine the reaction mechanism: Each hydroxyl group in fructose reacts with methyl iodide in the presence of silver oxide to form a methoxy group (-OCH3). This process is repeated for all hydroxyl groups, as the reaction is carried out with an excess of methyl iodide.
Account for the ketone group: The ketone group in fructose does not react with methyl iodide under these conditions, so it remains unchanged in the product.
Draw the final product: The final product is a fully methylated derivative of fructose, where all hydroxyl groups are converted to methoxy groups (-OCH3), and the ketone group remains intact. Represent this structure clearly, ensuring all substituents are shown.
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Fructose Structure and Reactivity
Fructose is a monosaccharide with a ketone functional group and multiple hydroxyl groups. Its structure allows it to undergo various chemical reactions, including alkylation. Understanding the specific sites of reactivity in fructose is crucial for predicting the products formed when it reacts with reagents like methyl iodide.
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06:06
Monosaccharides - Common Structures
Alkylation Reaction
Alkylation is a chemical reaction where an alkyl group is transferred to a nucleophile. In this case, methyl iodide acts as the alkylating agent, providing a methyl group that can attach to the hydroxyl groups of fructose. Recognizing how alkylation modifies the structure of fructose is essential for determining the final product.
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03:19Sodium Alkynide Alkylation
Role of Silver Oxide
Silver oxide serves as a base in this reaction, facilitating the deprotonation of the hydroxyl groups on fructose. This increases the nucleophilicity of the hydroxyl groups, making them more reactive towards methyl iodide. Understanding the role of silver oxide helps clarify how it influences the reaction mechanism and product formation.
Video consigliato:
03:02Silver Oxide Catalyzed Mechanism
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