-for-denominators-x2-9-x-3-and-6-assume-integer-factor-6-must-be-included-in-lcd

Question

Solve for xx:5x2−9+16=1x−3\displaystyle\frac{5}{$$x^2 - 9$$}+\frac{1}{6}=\frac{1}{x - 3}

Accepted Answer

x=3−6x=3-\sqrt6x=3+6x=3+\sqrt6

Answer

x=3x=3x=−3x=-3

Answer

x=3+6x=3+\sqrt6 only

Answer

x=3−6x=3-\sqrt6 only

Solve for xx:5x2−9+16=1x−3\(\displaystyle\)\(\frac{5}{x^2 - 9}\)+\(\frac{1}{6}\)=\(\frac{1}{x - 3}\)