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Rewrite the logarithmic equation as an exponential equation.
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Recall the definition of logarithms: if \(\log_b(x) = y\), then the equivalent exponential form is \(b^y = x\).
Identify the base \(b\), the logarithm result \(y\), and the argument \(x\) from the given equation \(\log_3\left(\frac{1}{27}\right) = -3\).
Here, the base is 3, the logarithm result is \(-3\), and the argument is \(\frac{1}{27}\).
Rewrite the logarithmic equation as an exponential equation by raising the base 3 to the power of \(-3\) and setting it equal to \(\frac{1}{27}\): \(3^{-3} = \frac{1}{27}\).
This shows the equivalence between the logarithmic and exponential forms without calculating the numerical value.