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Rewrite the exponential equation as a logarithmic equation.
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Recall the relationship between exponential and logarithmic forms: if \(a^{x} = b\), then the equivalent logarithmic form is \(\log_{a} b = x\).
Identify the base \(a\), the exponent \(x\), and the result \(b\) in the given exponential equation \(3^{x} = 9\).
Here, the base \(a\) is 3, the exponent is \(x\), and the result \(b\) is 9.
Rewrite the equation in logarithmic form by placing the base 3 as the base of the logarithm, the result 9 as the argument of the logarithm, and set it equal to the exponent \(x\).
The logarithmic form is therefore \(\log_{3} 9 = x\).