Simplify completely: $\frac{3(x^2+x-2)}{6(x+2)}$

$\frac{x-1}{2}$ and allows $x=-2$

$\frac{x-1}{2}$, with $x\ne -2$

$\frac{x+1}{2}$ with no exclusions

$\frac{x-1}{2(x+2)}$, with $x\ne 2$