Find the value of $\cos \frac{5\pi }{12}$ as $\cos (\frac{\pi }{6}+\frac{\pi }{4})$.

$\cos \left(\frac{5\pi }{12}\right)=\frac{\sqrt{6}+\sqrt{2}}{2}$

$\cos \left(\frac{5\pi }{12}\right)=\frac{\sqrt{6}-\sqrt{2}}{2}$

$\cos \left(\frac{5\pi }{12}\right)=\frac{\sqrt{6}+\sqrt{2}}{4}$

$\cos \left(\frac{5\pi }{12}\right)=\frac{\sqrt{6}-\sqrt{2}}{4}$