find-the-derivative-of-the-function-fx2cosx3sinx2cosx3sinxfleftxrightfrac2cos-x3

Question

Find the derivative of the function f(x)=2cos⁡x+3sin⁡x2cos⁡x−3sin⁡xf\left(x\right)=\frac{2\cos x+3\sin x}{2\cos x-3\sin x}.

Accepted Answer

f′(x)=12(2cos⁡x−3sin⁡$$x)2f^{\prime}$$\left(x\right)=\frac{12}{\left(2\cos x-3\sin x\$$right)^2$$}

Answer

f′(x)=122cos⁡x+3sin⁡$$xf^{\prime}$$\left(x\right)=\frac{12}{2\cos x+3\sin x}

Answer

f′(x)=122cos⁡x−3sin⁡$$xf^{\prime}$$\left(x\right)=\frac{12}{2\cos x-3\sin x}

Answer

f′(x)=12(2cos⁡x+3sin⁡$$x)2f^{\prime}$$\left(x\right)=\frac{12}{\left(2\cos x+3\sin x\$$right)^2$$}

Find the derivative of the function f(x)=2cosx+3sinx2cosx−3sinxf\(\left\)(x\(\right\))=\(\frac{2\cos x+3\sin x}{2\cos x-3\sin x}\).