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Question

Estimate the value of the convergent series ∑x=1∞(−1)xx3{\displaystyle\sum_{x=1}^{\infty}}\frac{\left(-1\$$right)^{x}$$}{$$x^3$$} with an absolute error less than 2×10−32\$$times10^{-3}. $$Round the answer to three decimal places.

Accepted Answer

−0.903-0.903

Answer

0.9030.903

Answer

0.3090.309

Answer

−0.309-0.309

Estimate the value of the convergent series ∑x=1∞(−1)xx3{\(\displaystyle\)\(\sum\)_{x=1}^{\(\infty\)}}\(\frac{\left(-1\right)^{x}\)}{x^3} with an absolute error less than 2×10−32\(\times\)10^{-3}. Round the answer to three decimal places.

Estimate the value of the convergent series $\sum_{x = 1}^{\infty} \frac{{(- 1)}^{x}}{x^{3}}$ with an absolute error less than $2 \times 10^{- 3}$ . Round the answer to three decimal places.