letpa14pa34pba35pafrac14paprimefrac34pbafrac35-and-pba12pbaprimefrac12-what-is-p

Question

Let P(A)=14,P(A′)=34,P(B∣A)=35,P(A)=\frac14,$$P(A^{\prime}$$)=\frac34,P(B|A)=\frac35, and P(B∣A′)=12P(B|$$A^{\prime}$$)=\frac{1}{2}. What is P(A∣B) P(A|B)  according to Bayes’ Theorem?

Accepted Answer

27\frac27

Answer

38\frac38

Answer

1119\frac{11}{19}

Answer

16\frac16

Let P(A)=14,P(A′)=34,P(B∣A)=35,P(A)=\(\frac\)14,P(A^{\(\prime\)})=\(\frac\)34,P(B|A)=\(\frac\)35, and P(B∣A′)=12P(B|A^{\(\prime\)})=\(\frac{1}{2}\). What is P(A∣B) P(A|B) according to Bayes’ Theorem?

Let $P (A) = \frac{1}{4}, P (A^{'}) = \frac{3}{4}, P (B ∣ A) = \frac{3}{5},$ and $P (B ∣ A^{'}) = \frac{1}{2}$ . What is $P (A ∣ B)$ according to Bayes’ Theorem?