evaluate-the-integral-2ex94e2xdxintfrac2ex9-4e2xdx

Question

Evaluate the integral: ∫2ex9+4e2xdx\int\frac{$$2e^{x}$$}{9 + $$4e^{2x}$$}dx

Accepted Answer

13tan⁡−1(2ex3)+C\frac{1}{3}\$$tan^{-1}$$\left(\frac{$$2e^{x}$$}{3}\right)+C

Answer

23tan⁡−1(2ex3)+C\frac23\$$tan^{-1}$$\left(\frac{$$2e^{x}$$}{3}\right)+C

Answer

13tan⁡−1(ex)+C\frac{1}{3}\$$tan^{-1}$$\$$left(e^{x}$$\right)+C

Answer

13tan⁡−1(ex3)+C\frac{1}{3}\$$tan^{-1}$$\left(\frac{$$e^{x}$$}{3}\right)+C

Evaluate the integral: ∫2ex9+4e2xdx\(\int\)\(\frac{2e^{x}\)}{9 + 4e^{2x}}dx