find-the-radius-rr-and-interval-of-convergence-for-the-power-series-n1y3nn2-disp

Question

Find the radius RR and interval of convergence for the power series ∑n=1∞y6nn2{\displaystyle\sum_{n=1}^{\infty}\frac{$$y^{6n}$$}{$$n^2$$}} using the Ratio Test.

Accepted Answer

R=1R=1[−1,1]\left\lbrack-1,1\right\rbrack

Answer

R=1R=1(−1,1)\left(-1,1\right)

Answer

R=2R=2(−2,2)\left(-2,2\right)

Answer

R=2R=2[−2,2]\left\lbrack-2,2\right\rbrack

Find the radius RR and interval of convergence for the power series ∑n=1∞y6nn2{\(\displaystyle\)\(\sum\)_{n=1}^{\(\infty\)}\(\frac{y^{6n}\)}{n^2}} using the Ratio Test.

Find the radius $R$ and interval of convergence for the power series $\sum_{n = 1}^{\infty} \frac{y^{6 n}}{n^{2}}$ using the Ratio Test.