for-the-series-m14m42m276m59m3-displaystylesumm1infty-frac4m4-2m2-76m5-9m-3-whic

Question

For the series ∑m=1∞4m4+2m2+76m5+9m+3 \displaystyle\sum_{m=1}^{\infty} \frac{$$4m^4$$ + $$2m^2 + 7$$}{$$6m^5 + 9m + 3$$} , which comparison series would you use with the Limit Comparison Test?

Accepted Answer

∑m=1∞1m{\displaystyle{\displaystyle{\sum_{m=1}^{\infty}}}\frac{1}{m}}

Answer

∑m=1∞1m4{{\displaystyle{\displaystyle{\sum_{m=1}^{\infty}}}\frac{1}{$$m^4$$}}}

Answer

∑m=1∞1m2{{\displaystyle{\displaystyle{\sum_{m=1}^{\infty}}}\frac{1}{$$m^2$$}}}

Answer

∑m=1∞1m3{{\displaystyle{\displaystyle{\sum_{m=1}^{\infty}}}\frac{1}{$$m^3$$}}}

For the series ∑m=1∞4m4+2m2+76m5+9m+3 \(\displaystyle\)\(\sum\)_{m=1}^{\(\infty\)} \(\frac{4m^4 + 2m^2 + 7}{6m^5 + 9m + 3}\) , which comparison series would you use with the Limit Comparison Test?

For the series $\sum_{m = 1}^{\infty} \frac{4 m^{4} + 2 m^{2} + 7}{6 m^{5} + 9 m + 3}$ , which comparison series would you use with the Limit Comparison Test?