Use a table of integrals to evaluate the definite integral:∫48d yyy2−16\$$int_4^8$$\frac{d\,y}{y\sqrt{$$y^2 - 16$$}}

Integrals Involving Inverse Trigonometric Functions

11. Integrals of Inverse, Exponential, & Logarithmic Functions / Integrals Involving Inverse Trigonometric Functions / Problema 4

Problema 4

Use a table of integrals to evaluate the definite integral:
$\int_{4}^{8} \frac{d y}{y \sqrt{y^{2} - 16}}$

$pi over 2$

$pi over 3$

$pi over 4$

$pi over 12$