a-fish-population-in-a-lake-is-initially-f0120-f0-120-the-growth-rate-is-given-b

Question

A fish population in a lake is initially F(0)=120 F(0) = 120 . The growth rate is given by F′(t)=25−$$t8F^{\prime}(t)=25$$-\frac{t}{8} (fish/month), for 0≤t≤160 0 \leq t \leq 160 , where t t  is in months. What is F(40) F(40) ?

Accepted Answer

10201020

Answer

880880

Answer

960960

Answer

12001200

A fish population in a lake is initially F(0)=120 F(0) = 120 . The growth rate is given by F′(t)=25−t8F^{\(\prime\)}(t)=25-\(\frac{t}{8}\) (fish/month), for 0≤t≤160 0 \(\leq\) t \(\leq\) 160 , where t t is in months. What is F(40) F(40) ?

A fish population in a lake is initially $F of 0 equals 120$ . The growth rate is given by $F^{'} (t) = 25 - \frac{t}{8}$ (fish/month), for $0 is less than or equal to t is less than or equal to 160$ , where $t$ is in months. What is $F of 40$ ?