find-the-derivative-of-the-function-y2x3x2yleft2xright3sqrtx-2

Question

Find the derivative of the function y=(2x)3x−2y=\left(2x\$$right)^{3\sqrt{x-2}$$}.

Accepted Answer

(2x)3x−2(3ln⁡2x2x−2+3x−2x)\left(2x\$$right)^{3\sqrt{x-2}$$}\left(\frac{3\ln2x}{2\sqrt{x-2}}+\frac{3\sqrt{x-2}}{x}\right)

Answer

(2x)3x−2(3ln⁡2x2x−2−3x−2x)\left(2x\$$right)^{3\sqrt{x-2}$$}\left(\frac{3\ln2x}{2\sqrt{x-2}}-\frac{3\sqrt{x-2}}{x}\right)

Answer

(2x)3x−2(3ln⁡2x2x−2+3x−22x)\left(2x\$$right)^{3\sqrt{x-2}$$}\left(\frac{3\ln2x}{2\sqrt{x-2}}+\frac{3\sqrt{x-2}}{2x}\right)

Answer

(2x)3x−2ln⁡2\left(2x\$$right)^{3\sqrt{x-2}$$}\ln2

Find the derivative of the function y=(2x)3x−2y=\(\left\)(2x\(\right\))^{3\(\sqrt{x-2}\)}.