convert-the-polar-equation-r2r10cos6sin0-r2-r10costheta-6sintheta-0-to-cartesian

Question

Convert the polar equation r2+r(10cos⁡θ−6sin⁡θ)=0 $$r^2 + r(10$$\cos	heta - 6\sin	heta) = 0  to Cartesian form and identify the curve.

Accepted Answer

(x+5)2+(y−3)2=$$34(x+5)^2$$ + $$(y-3)^2 = 34$$Circle

Answer

(x+5)2+(y−3)2=$$16(x+5)^2$+(y-3)^2=16$$Circle

Answer

(x−5)2+(y+3)2=$$34(x-5)^2$+(y+3)^2=34$$Circle

Answer

(x+5)2−(y−3)2=$$34(x+5)^2$-(y-3)^2=34$$Rectangular hyperbola

Convert the polar equation r2+r(10cosθ−6sinθ)=0 r^2 + r(10\(\cos\[\theta\) - 6\(\sin\]\theta\)) = 0 to Cartesian form and identify the curve.