solve-the-initial-value-problem-yx4xy24y02-yprimex-frac4xy2-4-y0-2-leave-your-an

Question

Solve the initial value problem y′(x)=4xy2−4,y(0)=2 $$y^{\prime}(x$$) = \frac{4x}{$$y^2 - 4$$}, y(0) = 2 . Leave your answer in implicit form.

Accepted Answer

y3−12y=6x2−$$16y^3-12y$$=$$6x^2-16$$

Answer

y3−12y=$$6x2+16y^3-12y$$=$$6x^2+16$$

Answer

y3+12y=6x2−$$16y^3+12y$$=$$6x^2-16$$

Answer

y3−4y=6x2−$$16y^3-4y$$=$$6x^2-16$$

Solve the initial value problem y′(x)=4xy2−4,y(0)=2 y^{\(\prime\)}(x) = \(\frac{4x}{y^2 - 4}\), y(0) = 2 . Leave your answer in implicit form.