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Ch. 1 - Functions
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 1, Problema 1.60

Solving equations Solve the following equations.


5(ˣ³) = 29

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Step 1: Start by isolating the term with the variable. Divide both sides of the equation by 5 to get x^3 = \(\frac{29}{5}\).
Step 2: To solve for x, take the cube root of both sides of the equation. This will give you x = \(\sqrt\)[3]{\(\frac{29}{5}\)}.
Step 3: Simplify the expression if possible. In this case, \(\sqrt\)[3]{\(\frac{29}{5}\)} is already in its simplest form.
Step 4: Consider the properties of cube roots. Remember that the cube root of a number can be positive or negative, but since we are dealing with real numbers, we focus on the principal (positive) root.
Step 5: Verify your solution by substituting x back into the original equation to ensure that both sides are equal.

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