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Ch. 10 - Sequences and Infinite Series
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 10, Problema 10.8.51

11–86. Applying convergence tests Determine whether the following series converge. Justify your answers.
∑ (from k = 1 to ∞)(7ᵏ + 11ᵏ) / 11ᵏ

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Rewrite the general term of the series to simplify it. The term is given by \( \frac{7^k + 11^k}{11^k} \). Split this into two separate fractions: \( \frac{7^k}{11^k} + \frac{11^k}{11^k} \).
Simplify each fraction: \( \frac{7^k}{11^k} = \left(\frac{7}{11}\right)^k \) and \( \frac{11^k}{11^k} = 1 \). So the general term becomes \( \left(\frac{7}{11}\right)^k + 1 \).
Analyze the behavior of the terms as \( k \to \infty \). Since \( \left(\frac{7}{11}\right)^k \to 0 \), the term approaches \( 1 \).
Recall the necessary condition for series convergence: if \( \lim_{k \to \infty} a_k \neq 0 \), then the series \( \sum a_k \) diverges. Here, the limit of the terms is 1, not 0.
Conclude that the series \( \sum_{k=1}^\infty \frac{7^k + 11^k}{11^k} \) diverges because its terms do not approach zero.

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