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Ch. 10 - Sequences and Infinite Series
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 10, Problema 10.2.47

13–52. Limits of sequences
Find the limit of the following sequences or determine that the sequence diverges.


{(1 / n)¹⁄ⁿ}

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Identify the given sequence: \(a_n = \left( \frac{1}{n} \right)^{\frac{1}{n}}\).
Rewrite the sequence using properties of exponents and logarithms to make the limit easier to analyze: \(a_n = e^{\ln \left( \left( \frac{1}{n} \right)^{\frac{1}{n}} \right)} = e^{\frac{1}{n} \ln \left( \frac{1}{n} \right)}\).
Simplify the exponent: \(\frac{1}{n} \ln \left( \frac{1}{n} \right) = \frac{1}{n} (-\ln n) = -\frac{\ln n}{n}\).
Analyze the limit of the exponent as \(n\) approaches infinity: \(\lim_{n \to \infty} -\frac{\ln n}{n}\). Recall that \(\ln n\) grows slower than \(n\), so this limit tends to zero.
Conclude the limit of the sequence by applying the limit to the exponential form: \(\lim_{n \to \infty} a_n = e^{\lim_{n \to \infty} -\frac{\ln n}{n}} = e^0\).

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Concetti chiave

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Limits of Sequences

The limit of a sequence is the value that the terms of the sequence approach as the index n goes to infinity. If the terms get arbitrarily close to a specific number, the sequence converges to that limit; otherwise, it diverges.
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Use of Logarithms in Limit Evaluation

Taking the natural logarithm of a sequence can simplify limit evaluation, especially for expressions involving exponents. By analyzing the limit of the logarithm, one can often find the original sequence's limit using continuity of the exponential function.
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