Ch. 11 - Power Series

Briggs - Calculus: Early Transcendentals 3rd Edition

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Briggs 3rd Edition

Ch. 11 - Power Series

Problema 11.R.51

Capitolo 11, Problema 11.R.51

Limits by power series Use Taylor series to evaluate the following limits.

lim ₙ → ₄ ln (x - 3)/(x² - 16)

Guida verificata passo dopo passo

First, recognize that the limit is as \(x\) approaches 4 for the expression \(\frac{\ln(x - 3)}{x^2 - 16}\). Notice that directly substituting \(x = 4\) gives \(\frac{\ln(1)}{16 - 16} = \frac{0}{0}\), an indeterminate form, so we need to use a series expansion to evaluate the limit.

Next, rewrite the denominator \(x^2 - 16\) as \((x - 4)(x + 4)\) to better understand its behavior near \(x = 4\).

Now, expand the numerator \(\ln(x - 3)\) as a Taylor series around \(x = 4\). Let \(h = x - 4\), so \(x - 3 = 1 + h\). The Taylor series for \(\ln(1 + h)\) around \(h = 0\) is \(\ln(1 + h) = h - \frac{h^2}{2} + \frac{h^3}{3} - \cdots\).

Similarly, express the denominator in terms of \(h\): \(x^2 - 16 = (4 + h)^2 - 16 = 8h + h^2\). This gives the denominator as \(8h + h^2\) near \(h = 0\).

Finally, write the original limit expression in terms of \(h\) using the expansions: \(\frac{h - \frac{h^2}{2} + \cdots}{8h + h^2}\). Simplify this expression by factoring out \(h\) from numerator and denominator, then analyze the limit as \(h \to 0\) to find the value of the limit.

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Taylor Series Expansion

A Taylor series represents a function as an infinite sum of terms calculated from the function's derivatives at a single point. It approximates functions near that point, allowing complex expressions to be simplified into polynomials, which are easier to analyze, especially for limits.

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When direct substitution in a limit leads to indeterminate forms, expressing functions as power series can help. By substituting the series expansions, one can simplify the expression and find the limit by analyzing the leading terms.

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Handling Indeterminate Forms

Limits that result in forms like 0/0 require special techniques to evaluate. Using series expansions or algebraic manipulation helps resolve these indeterminate forms by revealing the behavior of numerator and denominator near the point of interest.

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Approximating ln 2 Consider the following three ways to approximate

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