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Ch. 11 - Power Series
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 11, Problema 11.1.62

{Use of Tech} Number of terms What is the minimum order of the Taylor polynomial required to approximate the following quantities with an absolute error no greater than 10⁻³ ? (The answer depends on your choice of a center.)
ln 0.85

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Identify the function to approximate: here, it is \( f(x) = \ln(x) \). We want to approximate \( \ln(0.85) \) using a Taylor polynomial centered at some point \( a \).
Choose a center \( a \) close to 0.85 to ensure faster convergence and smaller error. A common choice is \( a = 1 \) because \( \ln(1) = 0 \) and derivatives of \( \ln(x) \) at 1 are easy to compute.
Write the Taylor series expansion of \( \ln(x) \) about \( a = 1 \): \[ \ln(x) = \ln(1) + \sum_{n=1}^{\infty} \frac{f^{(n)}(1)}{n!} (x - 1)^n \] where \( f^{(n)}(x) \) denotes the \( n \)-th derivative of \( \ln(x) \).
Determine the general form of the \( n \)-th derivative of \( \ln(x) \) at \( x=1 \) and write the Taylor polynomial of order \( N \) as: \[ P_N(x) = \sum_{n=1}^N \frac{(-1)^{n-1} (n-1)!}{n!} (x - 1)^n = \sum_{n=1}^N (-1)^{n-1} \frac{(x-1)^n}{n} \] (since the derivatives of \( \ln(x) \) at 1 follow a known pattern).
Use the Lagrange remainder formula to bound the absolute error: \[ |R_{N}(x)| = \left| \frac{f^{(N+1)}(c)}{(N+1)!} (x - 1)^{N+1} \right| \leq 10^{-3} \] where \( c \) is some number between \( x = 0.85 \) and \( a = 1 \). Find the smallest \( N \) such that this inequality holds.

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Taylor Polynomial Approximation

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