Domanda del libro di testo
Evaluate and simplify y'.
y = 2x√2
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Ch. 3 - Derivatives
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243
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TOC.tableOfContents
- Ch. 1 - Functions210
- Ch. 2 - Limits371
- Ch. 3 - Derivatives633
- Ch. 4 - Applications of the Derivative412
- Ch. 5 - Integration328
- Ch. 6 - Applications of Integration331
- Ch. 7 - Logarithmic, Exponential Functions, and Hyperbolic Functions177
- Ch. 8 - Integration Techniques394
- Ch. 9 - Differential Equations179
- Ch. 10 - Sequences and Infinite Series339
- Ch. 11 - Power Series218
- Ch.12 - Parametric and Polar Curves215
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 3, Problema 3.R.32
9–61. Evaluate and simplify y'.
y = csc⁵ 3x
Guida verificata passo dopo passo1
First, recognize that the problem involves differentiating a function. We need to find the derivative of y with respect to x, denoted as y'.
The given function is y = csc⁵(3x). To differentiate this, apply the chain rule. The chain rule states that if you have a composite function f(g(x)), the derivative is f'(g(x)) * g'(x).
Identify the outer function as f(u) = u⁵, where u = csc(3x). The derivative of u⁵ with respect to u is 5u⁴.
Next, differentiate the inner function u = csc(3x). The derivative of csc(x) is -csc(x)cot(x), so the derivative of csc(3x) is -csc(3x)cot(3x) * 3, using the chain rule again.
Combine these results using the chain rule: y' = 5(csc(3x))⁴ * (-csc(3x)cot(3x) * 3). Simplify the expression by multiplying the constants and combining like terms.
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Differentiation
Differentiation is a fundamental concept in calculus that involves finding the derivative of a function. The derivative represents the rate of change of the function with respect to its variable. In this case, we need to differentiate the function y = csc⁵(3x) to find y'.
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Percorso guidato
05:53
Finding Differentials
Chain Rule
The Chain Rule is a technique used in differentiation when dealing with composite functions. It states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function, multiplied by the derivative of the inner function. For y = csc⁵(3x), applying the Chain Rule is essential to correctly differentiate the function.
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05:02Intro to the Chain Rule
Trigonometric Derivatives
Trigonometric derivatives are the derivatives of trigonometric functions, which have specific rules. For example, the derivative of csc(x) is -csc(x)cot(x). Understanding these rules is crucial for differentiating y = csc⁵(3x), as we will need to apply the derivative of the csc function in our calculations.
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06:35Derivatives of Other Inverse Trigonometric Functions
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