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Ch. 3 - Derivatives
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 3, Problema 3.9.87.b

Explain why or why not. Determine whether the following statements are true and give an explanation or counterexample.


b. ln(x + 1) + ln(x − 1) = ln(x² − 1), for all x.

Guida verificata passo dopo passo
1
Step 1: Recall the logarithmic property that states \( \ln(a) + \ln(b) = \ln(ab) \). This property allows us to combine the logarithms on the left-hand side of the equation.
Step 2: Apply the property from Step 1 to the left-hand side: \( \ln(x + 1) + \ln(x - 1) = \ln((x + 1)(x - 1)) \).
Step 3: Simplify the expression \((x + 1)(x - 1)\) using the difference of squares formula: \((x + 1)(x - 1) = x^2 - 1\).
Step 4: Substitute the simplified expression from Step 3 back into the equation: \( \ln((x + 1)(x - 1)) = \ln(x^2 - 1) \).
Step 5: Conclude that the original statement \( \ln(x + 1) + \ln(x - 1) = \ln(x^2 - 1) \) is true for all \( x \) such that \( x > 1 \) or \( x < -1 \), because the domain of the logarithmic function requires that the arguments \( x + 1 \) and \( x - 1 \) are positive.

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Properties of Logarithms

Logarithms have specific properties that govern their behavior, such as the product, quotient, and power rules. The product rule states that ln(a) + ln(b) = ln(ab), while the quotient rule states that ln(a) - ln(b) = ln(a/b). Understanding these properties is essential for manipulating logarithmic expressions and verifying the validity of statements involving logarithms.
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Domain of Logarithmic Functions

The domain of a logarithmic function is restricted to positive real numbers. For the expression ln(x + 1) + ln(x - 1), both x + 1 and x - 1 must be greater than zero, which implies x must be greater than 1. Recognizing the domain is crucial for determining the validity of logarithmic equations and ensuring that all terms are defined.
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Counterexamples in Mathematics

A counterexample is a specific case that disproves a general statement. In the context of the given logarithmic equation, finding a value of x that makes the left-hand side unequal to the right-hand side serves as a counterexample. This method is vital in mathematical reasoning, as it helps to establish the truth or falsehood of statements by demonstrating exceptions.
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