Ch. 3 - Derivatives

Briggs - Calculus: Early Transcendentals 3rd Edition

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Briggs 3rd Edition

Ch. 3 - Derivatives

Problema 3.9.88

Capitolo 3, Problema 3.9.88

Find the following higher-order derivatives.

d²/dx² (In(x² + 1))

Guida verificata passo dopo passo

Step 1: Identify the function for which we need to find the second derivative. The function is $ f(x) = \ln(x^2 + 1) $.

Step 2: Find the first derivative of $ f(x) $. Use the chain rule: $ \frac{d}{dx}[\ln(u)] = \frac{1}{u} \cdot \frac{du}{dx} $, where $ u = x^2 + 1 $. Thus, $ \frac{d}{dx}[\ln(x^2 + 1)] = \frac{1}{x^2 + 1} \cdot \frac{d}{dx}[x^2 + 1] $.

Step 3: Differentiate $ x^2 + 1 $ with respect to $ x $. The derivative is $ \frac{d}{dx}[x^2 + 1] = 2x $. Substitute this back into the expression from Step 2 to get the first derivative: $ \frac{d}{dx}[\ln(x^2 + 1)] = \frac{2x}{x^2 + 1} $.

Step 4: Find the second derivative by differentiating the first derivative $ \frac{2x}{x^2 + 1} $ with respect to $ x $. Use the quotient rule: $ \frac{d}{dx}[\frac{v}{w}] = \frac{w \cdot \frac{dv}{dx} - v \cdot \frac{dw}{dx}}{w^2} $, where $ v = 2x $ and $ w = x^2 + 1 $.

Step 5: Calculate $ \frac{dv}{dx} = 2 $ and $ \frac{dw}{dx} = 2x $. Substitute these into the quotient rule formula to find the second derivative: $ \frac{d^2}{dx^2}[\ln(x^2 + 1)] = \frac{(x^2 + 1) \cdot 2 - 2x \cdot 2x}{(x^2 + 1)^2} $. Simplify the expression to complete the calculation.

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Higher-Order Derivatives

Higher-order derivatives refer to the derivatives of a function taken multiple times. The first derivative gives the rate of change of the function, the second derivative provides information about the curvature or concavity, and so on. In this context, finding the second derivative involves differentiating the function twice with respect to the variable.

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Higher Order Derivatives

Chain Rule

The chain rule is a fundamental differentiation technique used when differentiating composite functions. It states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function, multiplied by the derivative of the inner function. This rule is essential for correctly differentiating functions like In(x² + 1), where x² + 1 is the inner function.

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Intro to the Chain Rule

Natural Logarithm Function

The natural logarithm function, denoted as In(x), is the logarithm to the base e, where e is approximately 2.71828. It is important in calculus because it has unique properties, such as its derivative being 1/x. Understanding how to differentiate the natural logarithm, especially in the context of composite functions, is crucial for solving the given problem.

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Derivative of the Natural Logarithmic Function

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