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Ch. 4 - Applications of the Derivative
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 4, Problema 4.7.41

17–83. Limits Evaluate the following limits. Use l’Hôpital’s Rule when it is convenient and applicable.


lim_x→∞ (e¹/ₓ - 1)/(1/x)

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First, identify the form of the limit as x approaches infinity. Substitute x with infinity in the expression (e^(1/x) - 1)/(1/x) to see if it results in an indeterminate form like 0/0 or ∞/∞.
Notice that as x approaches infinity, 1/x approaches 0. Therefore, e^(1/x) approaches e^0, which is 1. This makes the numerator e^(1/x) - 1 approach 0, and the denominator 1/x also approaches 0, resulting in the indeterminate form 0/0.
Since the limit is in the indeterminate form 0/0, l'Hôpital's Rule can be applied. According to l'Hôpital's Rule, take the derivative of the numerator and the derivative of the denominator separately.
The derivative of the numerator e^(1/x) - 1 with respect to x is found using the chain rule. The derivative of e^(1/x) is e^(1/x) multiplied by the derivative of 1/x, which is -1/x². Therefore, the derivative of the numerator is -e^(1/x)/x².
The derivative of the denominator 1/x with respect to x is -1/x². Now, apply l'Hôpital's Rule by substituting these derivatives into the limit: lim_x→∞ (-e^(1/x)/x²)/(-1/x²). Simplify the expression and evaluate the limit as x approaches infinity.

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