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Ch. 4 - Applications of the Derivative
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 4, Problema 4.7.20

Evaluate the following limits. Use l’Hôpital’s Rule when it is convenient and applicable.


lim_x→ 0 (eˣ - 1) / (2x + 5)

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First, substitute x = 0 into the limit expression to check if it results in an indeterminate form. The expression becomes (e^0 - 1) / (2*0 + 5), which simplifies to 0/5 = 0. Since this is not an indeterminate form, l'Hôpital's Rule is not necessary.
Since the limit does not result in an indeterminate form, evaluate the expression directly by substituting x = 0. The expression becomes (e^0 - 1) / (2*0 + 5).
Simplify the expression: e^0 is 1, so the numerator becomes 1 - 1 = 0. The denominator is 2*0 + 5 = 5.
The limit simplifies to 0/5, which is 0.
Thus, the limit of (eˣ - 1) / (2x + 5) as x approaches 0 is 0.

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