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Ch. 4 - Applications of the Derivative
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 4, Problema 4.5.65

Crankshaft A crank of radius r rotates with an angular frequency w It is connected to a piston by a connecting rod of length L (see figure). The acceleration of the piston varies with the position of the crank according to the function <IMAGE>


a (Θ) = w²r (cos Θ + (r cos2Θ) / L) .


For fixed w , L, and r find the values of Θ, with 0 ≤ Θ ≤ 2π , for which the acceleration of the piston is a maximum and minimum.

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First, understand that the problem involves finding the extrema (maximum and minimum values) of the function a(Θ) = w²r (cos Θ + (r cos²Θ) / L) with respect to Θ, where 0 ≤ Θ ≤ 2π.
To find the extrema, we need to take the derivative of a(Θ) with respect to Θ. This involves using the chain rule and product rule for differentiation.
Set the derivative, da/dΘ, equal to zero to find the critical points. These are the values of Θ where the acceleration could be at a maximum or minimum.
Evaluate the second derivative, d²a/dΘ², at the critical points to determine the nature of each critical point (i.e., whether it is a maximum, minimum, or a point of inflection).
Finally, evaluate the original function a(Θ) at the critical points and the endpoints Θ = 0 and Θ = 2π to determine the absolute maximum and minimum values of the acceleration within the given interval.

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Angular Motion

Angular motion describes the rotation of an object around a central point or axis. In this context, the crankshaft rotates with an angular frequency, denoted by ω, which is the rate of change of the angular position θ over time. Understanding angular motion is crucial for analyzing how the crankshaft's rotation affects the piston's movement.
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Derivatives Applied To Velocity

Trigonometric Functions

Trigonometric functions, such as cosine, are essential in describing periodic phenomena like rotational motion. In the given function a(Θ) = ω²r (cos Θ + (r cos2Θ) / L), the cosine terms represent the angular position's influence on the piston's acceleration. Mastery of trigonometric identities and properties is necessary to manipulate and analyze these expressions effectively.
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Introduction to Trigonometric Functions

Optimization in Calculus

Optimization involves finding the maximum or minimum values of a function, which is a common application of calculus. To determine the values of Θ that maximize or minimize the piston's acceleration, one must use techniques such as taking derivatives and setting them to zero to find critical points, then applying the second derivative test or analyzing endpoints within the given interval.
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Intro to Applied Optimization: Maximizing Area
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5–7. For each function ƒ and interval [a, b], a graph of ƒ is given along with the secant line that passes though the graph of ƒ at x = a and x = b.



a. Use the graph to make a conjecture about the value(s) of c satisfying the equation (ƒ(b) - ƒ(a)) / (b-a) = ƒ' (c) .


b. Verify your answer to part (a) by solving the equation (ƒ(b) - ƒ(a)) / (b-a) = ƒ' (c) for c.



ƒ(x) = x² / 4 + 1 ; [ -2, 4] <IMAGE>

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Second Derivative Test Locate the critical points of the following functions. Then use the Second Derivative Test to determine (if possible) whether they correspond to local maxima or local minima.


f(x) = x³ - 13x² - 9x

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17–83. Limits Evaluate the following limits. Use l’Hôpital’s Rule when it is convenient and applicable.


lim_x→π (cos x +1 ) / (x - π )²

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17–83. Limits Evaluate the following limits. Use l’Hôpital’s Rule when it is convenient and applicable.


lim_x→ 0 (sin² 3x) / x²

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Increasing and decreasing functions. Find the intervals on which f is increasing and the intervals on which it is decreasing.


f(x) = (x - 1)²

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Sketch the graph of a continuous function ƒ on [0, 4] satisfying the given properties.


ƒ' (x) and ƒ'3 are undefined; ƒ'(2) = 0; has a local maximum at x= 1; ƒ has local minimum at x = 2; and ƒ has an absolute maximum at x= 3; and ƒ has an absolute minimum at x = 4 .

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