Question

The figure shows six containers, each of which is filled from the top. Assume water is poured into the containers at a constant rate and each container is filled in 10 s. Assume also that the horizontal cross sections of the containers are always circles. Let h (t) be the depth of water in the container at time t, for 0 ≤ t ≤ 10 . <IMAGE>

d. For each container, where does h' (the derivative of h ) have an absolute maximum on [0 , 10]?

Accepted Answer

Understand that the problem involves finding the absolute maximum of the derivative of the depth of water, h'(t), in each container over the interval [0, 10]. Recognize that h'(t) represents the rate of change of the water depth with respect to time. Since water is poured at a constant rate, the volume of water added per unit time is constant. Consider the shape of each container. The rate at which the water level rises, h'(t), depends on the cross-sectional area of the container at the water level. A smaller cross-sectional area results in a faster rise in water level. For each container, identify the point where the cross-sectional area is smallest, as this is where h'(t) will be maximized. This typically occurs at the narrowest part of the container. Evaluate the behavior of h'(t) at the endpoints of the interval [0, 10] and at any critical points found in the previous step to determine where the absolute maximum occurs.

Risposta video verificata per un problema simile:

Concetti chiave

Derivatives

Critical Points

Absolute Maximum