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Ch. 4 - Applications of the Derivative
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 4, Problema 4.R.118b

{Use of Tech} A family of superexponential functions Let ƒ(x) = (a + x)ˣ , where a > 0.




b. Describe the end behavior of f (near the left boundary of its domain and as x→∞).

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First, identify the domain of the function ƒ(x) = (a + x)ˣ. Since the base (a + x) must be positive, the domain is x > -a.
Consider the behavior of ƒ(x) as x approaches the left boundary of its domain, which is x approaching -a from the right. As x gets closer to -a, the base (a + x) approaches zero, and the exponent x approaches -a. This results in the function approaching zero.
Next, analyze the behavior of ƒ(x) as x approaches infinity. As x becomes very large, both the base (a + x) and the exponent x increase. The function (a + x)ˣ grows rapidly, leading to superexponential growth.
Understand that superexponential growth means the function increases faster than exponential functions, due to the variable being both in the base and the exponent.
Summarize the end behavior: Near the left boundary of its domain, ƒ(x) approaches zero as x approaches -a. As x approaches infinity, ƒ(x) exhibits superexponential growth, increasing very rapidly.

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Superexponential Functions

Superexponential functions, like f(x) = (a + x)ˣ, grow faster than exponential functions as x increases. This means that as x approaches infinity, the function's value increases at an accelerating rate, which is crucial for understanding its end behavior.
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End behavior refers to the behavior of a function as the input approaches certain limits, such as negative or positive infinity. For f(x) = (a + x)ˣ, analyzing end behavior involves determining how the function behaves as x approaches the left boundary of its domain and as x approaches infinity.
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