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Ch. 5 - Integration
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Tutti i libri di testoBriggs 3rd EditionCh. 5 - IntegrationProblema 5.3.87c
Capitolo 5, Problema 5.3.87c

Matching functions with area functions Match the functions ƒ, whose graphs are given in a― d, with the area functions A (𝓍) = ∫₀ˣ ƒ(t) dt, whose graphs are given in A–D.


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Guida verificata passo dopo passo
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Observe the graph of the function f(t) in the first image. The graph is a parabola that starts at the origin, increases to a maximum point, and then decreases back to zero at t = b. This indicates that f(t) is positive over the interval [0, b], and the area under the curve will first increase and then decrease as x approaches b.
Recall that the area function A(x) = ∫₀ˣ f(t) dt represents the accumulated area under the curve of f(t) from t = 0 to t = x. Since f(t) is positive, A(x) will initially increase as x increases. However, as f(t) decreases after the maximum point, the rate of increase of A(x) will slow down, and A(x) will eventually stop increasing when x = b.
Compare the behavior of A(x) with the given graphs (A–D). The graph of A(x) that matches this behavior will start at 0, increase to a maximum value, and then decrease back to 0 at x = b. This matches the graph labeled (B).
Verify the match by considering the derivative relationship: A'(x) = f(x). The derivative of the area function A(x) should match the shape of f(t). Since the graph of A(x) in (B) has a slope that increases, reaches a maximum, and then decreases, it aligns with the shape of f(t) in the first image.
Conclude that the function f(t) in the first image corresponds to the area function A(x) in graph (B).

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Definite Integral

A definite integral represents the signed area under a curve defined by a function f(t) from a lower limit to an upper limit. It is denoted as ∫ₐᵇ f(t) dt, where 'a' and 'b' are the bounds of integration. This concept is crucial for understanding how the area function A(x) accumulates the values of f(t) as x varies from 0 to x.
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Definition of the Definite Integral

Area Function

The area function A(x) is defined as A(x) = ∫₀ˣ f(t) dt, which calculates the total area under the curve of f(t) from 0 to x. This function provides insight into how the area changes as x increases, and its graph typically reflects the accumulation of area, showing increasing or decreasing trends based on the behavior of f(t).
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Finding Area When Bounds Are Not Given

Relationship Between Functions and Their Area Functions

The relationship between a function f(t) and its area function A(x) is characterized by the Fundamental Theorem of Calculus, which states that the derivative of the area function A(x) is equal to the original function f(t). This means that the slope of the area function at any point x corresponds to the value of the function f(t) at that point, linking the two concepts through differentiation and integration.
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Finding Area Between Curves on a Given Interval
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                                                                                                                                                                                     (b) Suppose ƒ is a negative increasing function, for 𝓍 > 0 . Then the area function A(𝓍) = ∫₀ˣ ƒ(t) dt is a decreasing function of 𝓍 .

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