Ch. 5 - Integration

Briggs - Calculus: Early Transcendentals 3rd Edition

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Briggs 3rd Edition

Ch. 5 - Integration

Problema 5.4.46a

Capitolo 5, Problema 5.4.46a

Planetary orbits The planets orbit the Sun in elliptical orbits with the Sun at one focus (see Section 12.4 for more on ellipses). The equation of an ellipse whose dimensions are 2a in the 𝓍-direction and 2b in the y-direction is (𝓍²/a²) + (y² /b²) = 1.
(a) Let d² denote the square of the distance from a planet to the center of the ellipse at (0, 0). Integrate over the interval [ ―a, a] to show that the average value of d² is (a² + 2b²) /3 .

Guida verificata passo dopo passo

Step 1: Begin by recalling the equation of the ellipse: (𝓍²/a²) + (y²/b²) = 1. This represents the elliptical orbit of the planet with semi-major axis 'a' and semi-minor axis 'b'.

Step 2: The square of the distance from the planet to the center of the ellipse is given by d² = 𝓍² + y². Substitute y² from the ellipse equation into this expression: y² = b²(1 - 𝓍²/a²). Thus, d² = 𝓍² + b²(1 - 𝓍²/a²).

Step 3: Simplify the expression for d²: d² = 𝓍² + b² - (b²𝓍²/a²). Combine terms to get d² = (1 - b²/a²)𝓍² + b².

Step 4: To find the average value of d² over the interval [−a, a], use the formula for the average value of a function: (1/(a - (-a))) ∫[−a, a] d² d𝓍. This simplifies to (1/(2a)) ∫[−a, a] [(1 - b²/a²)𝓍² + b²] d𝓍.

Step 5: Break the integral into two parts: (1/(2a)) [∫[−a, a] (1 - b²/a²)𝓍² d𝓍 + ∫[−a, a] b² d𝓍]. Evaluate each integral separately, noting that ∫[−a, a] 𝓍² d𝓍 = (2/3)a³ and ∫[−a, a] d𝓍 = 2a. Combine results to show that the average value of d² is (a² + 2b²)/3.

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Elliptical Orbits

Elliptical orbits describe the paths that celestial bodies, such as planets, take around a focal point, like the Sun. An ellipse is defined by its semi-major axis (a) and semi-minor axis (b), with the Sun located at one of the foci. Understanding the properties of ellipses is crucial for analyzing planetary motion and calculating distances within these orbits.

Average Value of a Function

The average value of a function over a given interval is calculated by integrating the function over that interval and then dividing by the length of the interval. In this context, the average value of the square of the distance from a planet to the center of the ellipse is derived through integration, which provides insights into the planet's position relative to the Sun over its orbital path.

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Average Value of a Function

Integration

Integration is a fundamental concept in calculus that involves finding the accumulated area under a curve represented by a function. In this problem, integration is used to compute the average value of the squared distance from the center of the ellipse, which requires setting up the appropriate integral and evaluating it over the specified interval. Mastery of integration techniques is essential for solving problems related to areas, volumes, and averages in calculus.

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Integration by Parts for Definite Integrals

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