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Ch. 5 - Integration
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 5, Problema 5.2.53b

Properties of integrals Suppose ∫₀³ƒ(𝓍) d𝓍 = 2 , ∫₃⁶ƒ(𝓍) d𝓍 = ―5 , and ∫₃⁶g(𝓍) d𝓍 = 1. Evaluate the following integrals.
(b) ∫₃⁶ (―3g(𝓍)) d𝓍

Guida verificata passo dopo passo
1
Step 1: Recall the property of integrals that allows you to factor out constants. Specifically, for any constant c and function g(x), ∫ₐᵇ c·g(x) dx = c·∫ₐᵇ g(x) dx.
Step 2: Apply this property to the given integral ∫₃⁶ (―3g(𝓍)) d𝓍. Here, the constant is ―3, so the integral becomes ―3·∫₃⁶ g(𝓍) d𝓍.
Step 3: Substitute the value of ∫₃⁶ g(𝓍) d𝓍, which is provided as 1, into the expression from Step 2.
Step 4: Multiply the constant ―3 by the value of the integral ∫₃⁶ g(𝓍) d𝓍 to simplify the expression.
Step 5: The result of the multiplication gives the value of the integral ∫₃⁶ (―3g(𝓍)) d𝓍. Ensure you understand how the constant factor affects the integral.

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Properties of Integrals

The properties of integrals, particularly the linearity property, state that the integral of a sum of functions is the sum of their integrals, and that a constant can be factored out of an integral. This means that for any constant 'c' and function 'f(x)', ∫c f(x) dx = c ∫f(x) dx. Understanding these properties is essential for simplifying and evaluating integrals.
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Properties of Functions

Definite Integrals

Definite integrals represent the signed area under a curve between two limits. The notation ∫ₐᵇ f(x) dx indicates the integral of f(x) from 'a' to 'b'. The value of a definite integral can be interpreted as the accumulation of quantities, and it can be positive, negative, or zero depending on the function's behavior over the interval.
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Definition of the Definite Integral

Substitution in Integrals

Substitution is a technique used in integration to simplify the process by changing the variable of integration. This method often involves setting u = g(x) for some function g, which transforms the integral into a more manageable form. Understanding how to apply substitution effectively can greatly aid in evaluating complex integrals.
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