Skip to main content
Ch. 8 - Integration Techniques
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 8, Problema 8.4.59

59. Area of a segment of a circle
Use two approaches to show that the area of a cap (or segment) of a circle of radius r subtended by an angle θ (see figure) is given by:
A_seg = (1/2) r² (θ - sin θ)
b. Find the area using calculus.
<IMAGE>

Guida verificata passo dopo passo
1
Step 1: Understand the problem setup. We want to find the area of the segment (or cap) of a circle with radius \(r\) subtended by a central angle \(\theta\). The segment is the region bounded by the chord and the arc corresponding to \(\theta\).
Step 2: Express the circle in Cartesian coordinates. Place the circle centered at the origin with equation \(x^2 + y^2 = r^2\). The segment lies above the chord, so we consider the upper semicircle: \(y = \sqrt{r^2 - x^2}\).
Step 3: Determine the limits of integration. The chord endpoints correspond to the angle \(\pm \frac{\theta}{2}\) from the positive x-axis. The x-coordinates of these points are \(x = r \cos \frac{\theta}{2}\) and \(x = r\) (assuming the segment is on the right side). We integrate from \(x = r \cos \frac{\theta}{2}\) to \(x = r\).
Step 4: Set up the integral for the area of the segment. The area under the curve (arc) from \(x = r \cos \frac{\theta}{2}\) to \(x = r\) is \(\int_{r \cos \frac{\theta}{2}}^{r} \sqrt{r^2 - x^2} \, dx\). The area of the triangle formed by the chord and the radius lines is \(\frac{1}{2} r^2 \sin \theta\). The segment area is the difference between the sector area and the triangle area.
Step 5: Use calculus to evaluate the integral and subtract the triangle area. The integral \(\int \sqrt{r^2 - x^2} \, dx\) can be solved using a trigonometric substitution, and after evaluating the definite integral and subtracting the triangle area, you will arrive at the formula for the segment area: \(A_{seg} = \frac{1}{2} r^2 (\theta - \sin \theta)\).

Risposta video verificata per un problema simile:

Questa soluzione video è stata consigliata dai nostri tutor come utile per risolvere questo problema.
Durata del video:
7m

Concetti chiave

Ecco i concetti essenziali che devi comprendere per rispondere correttamente alla domanda.

Area of a Sector of a Circle

The area of a sector of a circle with radius r subtended by an angle θ (in radians) is given by (1/2)r²θ. This formula represents the portion of the circle's area enclosed by two radii and the arc between them, serving as a foundational step in finding the segment area.
Video consigliato:
Percorso guidato
07:45
Area of Polar Regions

Area of a Triangle Using Trigonometry

The triangle formed by the two radii and the chord can be calculated using the formula (1/2)r²sinθ, where θ is the angle between the radii. This area is subtracted from the sector area to find the segment area, linking trigonometric functions with geometric areas.
Video consigliato:
Percorso guidato
6:04
Introduction to Trigonometric Functions

Definite Integration in Polar Coordinates

Using calculus, the area of the segment can be found by integrating the function describing the circle's boundary in polar coordinates. The integral from 0 to θ of (1/2)r² dθ minus the triangle area yields the segment area, demonstrating the application of definite integrals to find areas bounded by curves.
Video consigliato:
05:32
Intro to Polar Coordinates