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Ch. 8 - Integration Techniques
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 8, Problema 8.9.74

77–86. Comparison Test Determine whether the following integrals converge or diverge.
84. ∫(from 1 to ∞) (2 + cos x) / x² dx

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1
Identify the integral to analyze: \(\int_{1}^{\infty} \frac{2 + \cos x}{x^{2}} \, dx\) and note that it is an improper integral because the upper limit is infinity.
Recall the Comparison Test for improper integrals: if \(0 \leq f(x) \leq g(x)\) for all \(x\) in \([1, \infty)\) and \(\int_{1}^{\infty} g(x) \, dx\) converges, then \(\int_{1}^{\infty} f(x) \, dx\) also converges.
Find a suitable function \(g(x)\) to compare with \(f(x) = \frac{2 + \cos x}{x^{2}}\). Since \(\cos x\) oscillates between \(-1\) and \(1\), the numerator \(2 + \cos x\) is bounded between \(1\) and \(3\). Therefore, \(\frac{2 + \cos x}{x^{2}} \leq \frac{3}{x^{2}}\) for all \(x \geq 1\).
Check the convergence of the comparison integral \(\int_{1}^{\infty} \frac{3}{x^{2}} \, dx\). Since \(\int_{1}^{\infty} \frac{1}{x^{2}} \, dx\) converges (p-integral with \(p=2 > 1\)), multiplying by a constant 3 does not affect convergence.
Conclude by the Comparison Test that since \(\int_{1}^{\infty} \frac{3}{x^{2}} \, dx\) converges and \(\frac{2 + \cos x}{x^{2}} \leq \frac{3}{x^{2}}\), the original integral \(\int_{1}^{\infty} \frac{2 + \cos x}{x^{2}} \, dx\) also converges.

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Improper integrals involve integration over an infinite interval or where the integrand has an infinite discontinuity. To evaluate convergence, we consider the limit of the integral as the upper bound approaches infinity. Understanding this concept is essential for determining whether the integral converges or diverges.
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