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Ch. 9 - Differential Equations
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 9, Problema 9.R.3

2–10. General solutions Use the method of your choice to find the general solution of the following differential equations.
y′(t) + 2y = 6

Guida verificata passo dopo passo
1
Identify the type of differential equation. The given equation \(y'(t) + 2y = 6\) is a first-order linear ordinary differential equation.
Rewrite the equation in the standard linear form: \(y' + P(t)y = Q(t)\), where \(P(t) = 2\) and \(Q(t) = 6\).
Find the integrating factor (IF) using the formula \(\mu(t) = e^{\int P(t)\,dt}\). Here, calculate \(\mu(t) = e^{\int 2\,dt} = e^{2t}\).
Multiply both sides of the differential equation by the integrating factor \(e^{2t}\) to get \(e^{2t}y' + 2e^{2t}y = 6e^{2t}\). Notice that the left side is the derivative of \(e^{2t}y\).
Integrate both sides with respect to \(t\): \(\int \frac{d}{dt}(e^{2t}y)\,dt = \int 6e^{2t}\,dt\). Then solve for \(y(t)\) by dividing by \(e^{2t}\) and include the constant of integration.

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Concetti chiave

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First-Order Linear Differential Equations

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