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Ch. 9 - Differential Equations
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 9, Problema 9.1.27

21–32. Finding general solutions Find the general solution of each differential equation. Use C,C1,C2... to denote arbitrary constants.
u''(x) = 55x⁹ + 36x⁷ - 21x⁵ + 10x⁻³

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1
Recognize that the given differential equation is a second-order ordinary differential equation of the form \(u''(x) = f(x)\), where \(f(x) = 55x^{9} + 36x^{7} - 21x^{5} + 10x^{-3}\).
To find the general solution \(u(x)\), integrate the right-hand side function \(f(x)\) twice with respect to \(x\). The first integration will give \(u'(x)\), and the second integration will give \(u(x)\).
Perform the first integration: calculate \(u'(x) = \int (55x^{9} + 36x^{7} - 21x^{5} + 10x^{-3}) \, dx\). Integrate each term separately using the power rule for integration, which states \(\int x^{n} \, dx = \frac{x^{n+1}}{n+1} + C\) for \(n \neq -1\).
After finding \(u'(x)\), perform the second integration: calculate \(u(x) = \int u'(x) \, dx\). Again, integrate each term separately and add a new arbitrary constant of integration.
Combine the results to write the general solution as $u(x) = $ (the expression from the second integration) \(+ C_1 x + C_2\), where \(C_1\) and \(C_2\) are arbitrary constants representing the general solution's family.

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