Skip to main content
Ch. 9 - Differential Equations
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Non è quello che usi tu?Cambia libro di testo
Capitolo 9, Problema 9.2.2

Consider the differential equation y'(t) = t² - 3y² and the solution curve that passes through the point (3, 1). What is the slope of the curve at (3, 1)?

Guida verificata passo dopo passo
1
Identify the given differential equation: \(y'(t) = t^{2} - 3y^{2}\).
Recognize that \(y'(t)\) represents the slope of the solution curve at any point \((t, y)\).
Substitute the given point \((t, y) = (3, 1)\) into the differential equation to find the slope at that point.
Calculate the value of the right-hand side by plugging in \(t = 3\) and \(y = 1\): \(3^{2} - 3 \times 1^{2}\).
Simplify the expression to find the slope \(y'(3)\) at the point \((3, 1)\).

Risposta video verificata per un problema simile:

Questa soluzione video è stata consigliata dai nostri tutor come utile per risolvere questo problema.
Durata del video:
1m

Concetti chiave

Ecco i concetti essenziali che devi comprendere per rispondere correttamente alla domanda.

Differential Equation

A differential equation relates a function with its derivatives, describing how the function changes. In this problem, y'(t) represents the derivative of y with respect to t, indicating the slope of the solution curve at any point.
Video consigliato:
07:39
Classifying Differential Equations

Evaluating the Derivative at a Point

To find the slope of the solution curve at a specific point, substitute the given values of t and y into the differential equation. This gives the instantaneous rate of change or slope at that point.
Video consigliato:
5:14
Evaluate Logarithms

Initial Condition and Solution Curve

The initial condition (3, 1) specifies a point through which the solution curve passes. It helps identify the particular solution of the differential equation and allows evaluation of the slope at that exact point.
Video consigliato:
Percorso guidato
05:03
Initial Value Problems
Pratica correlata