Skip to main content
Ch. 10 - Infinite Sequences and Series
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 10, Problema 10.PE.68

Maclaurin Series
Find Taylor series at x = 0 for the functions in Exercises 63–70.
cos (x³/√5)

Guida verificata passo dopo passo
1
Recall that the Maclaurin series is a Taylor series expansion of a function at \(x = 0\). It can be written as \(f(x) = \sum_{n=0}^{\infty} \frac{f^{(n)}(0)}{n!} x^n\).
Identify the function to expand: \(f(x) = \cos\left(\frac{x^3}{\sqrt{5}}\right)\). Notice that the argument of cosine is \(\frac{x^3}{\sqrt{5}}\).
Recall the Maclaurin series expansion for \(\cos z\) is \(\cos z = \sum_{n=0}^{\infty} (-1)^n \frac{z^{2n}}{(2n)!}\), where \(z\) is any expression.
Substitute \(z = \frac{x^3}{\sqrt{5}}\) into the cosine series to get \(\cos\left(\frac{x^3}{\sqrt{5}}\right) = \sum_{n=0}^{\infty} (-1)^n \frac{\left(\frac{x^3}{\sqrt{5}}\right)^{2n}}{(2n)!}\).
Simplify the powers and write the series explicitly as \(\sum_{n=0}^{\infty} (-1)^n \frac{x^{6n}}{(2n)! (\sqrt{5})^{2n}}\). This is the Maclaurin series for the given function.

Risposta video verificata per un problema simile:

Questa soluzione video è stata consigliata dai nostri tutor come utile per risolvere questo problema.
Durata del video:
2m

Concetti chiave

Ecco i concetti essenziali che devi comprendere per rispondere correttamente alla domanda.

Maclaurin Series

A Maclaurin series is a special case of the Taylor series expanded at x = 0. It represents a function as an infinite sum of its derivatives at zero, multiplied by powers of x and divided by factorial terms. This series helps approximate functions near zero.
Video consigliato:
08:26
Convergence of Taylor & Maclaurin Series

Taylor Series Expansion

The Taylor series expresses a function as an infinite sum of terms calculated from the function's derivatives at a specific point. For a function f(x), the series at x = a is given by f(a) plus derivatives evaluated at a, scaled by powers of (x - a). When a = 0, it becomes the Maclaurin series.
Video consigliato:
08:42
Taylor Series

Series Expansion of Composite Functions

When dealing with functions like cos(x³/√5), the series expansion involves substituting the inner function into the known series of the outer function. This requires understanding how to replace variables in standard series and simplify powers and coefficients accordingly.
Video consigliato:
Percorso guidato
06:00
Geometric Series