Skip to main content
Ch. 10 - Infinite Sequences and Series
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 10, Problema 10.10.29

Use series to evaluate the limits in Exercises 29–40.
29. lim (x → 0) (e^x - (1 + x)) / x²

Guida verificata passo dopo passo
1
Recall the Maclaurin series expansion for the exponential function \(e^x\), which is given by: \[e^x = 1 + x + \frac{x^2}{2!} + \frac{x^3}{3!} + \frac{x^4}{4!} + \cdots\]
Substitute the series expansion of \(e^x\) into the given limit expression: \[\lim_{x \to 0} \frac{e^x - (1 + x)}{x^2} = \lim_{x \to 0} \frac{\left(1 + x + \frac{x^2}{2!} + \frac{x^3}{3!} + \cdots\right) - (1 + x)}{x^2}\]
Simplify the numerator by canceling out the \(1\) and \(x\) terms: \[\lim_{x \to 0} \frac{\frac{x^2}{2!} + \frac{x^3}{3!} + \cdots}{x^2}\]
Divide each term in the numerator by \(x^2\): \[\lim_{x \to 0} \left( \frac{1}{2!} + \frac{x}{3!} + \frac{x^2}{4!} + \cdots \right)\]
Evaluate the limit as \(x\) approaches 0 by substituting \(x = 0\) into the simplified expression, which leaves only the constant term(s).

Risposta video verificata per un problema simile:

Questa soluzione video è stata consigliata dai nostri tutor come utile per risolvere questo problema.
Durata del video:
6m

Concetti chiave

Ecco i concetti essenziali che devi comprendere per rispondere correttamente alla domanda.

Taylor Series Expansion

A Taylor series represents a function as an infinite sum of terms calculated from the function's derivatives at a single point. For functions like e^x, the series expansion around x=0 (Maclaurin series) helps approximate the function using polynomials, which simplifies limit evaluation.
Video consigliato:
08:42
Taylor Series

Limit Evaluation Using Series

By substituting the series expansion into the limit expression, complex functions can be approximated by polynomials. This allows direct simplification and evaluation of limits, especially when the original expression results in indeterminate forms like 0/0.
Video consigliato:
Percorso guidato
06:00
Geometric Series

Handling Indeterminate Forms

Limits that yield forms like 0/0 require algebraic manipulation or series expansion to resolve. Using series expansions helps rewrite the numerator and denominator to identify the leading terms, enabling the determination of the limit's value.
Video consigliato:
Percorso guidato
6:20
Circles in General Form