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Ch. 2 - Limits and Continuity
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 2, Problema 2.6.86

Finding Limits of Differences When x → ±∞


Find the limits in Exercises 84–90. (Hint: Try multiplying and dividing by the conjugate.)


lim x → −∞ (√(x² + 3) + x)

Guida verificata passo dopo passo
1
Identify the expression for which you need to find the limit: \( \lim_{x \to -\infty} (\sqrt{x^2 + 3} + x) \).
To simplify the expression, multiply and divide by the conjugate: \( \frac{(\sqrt{x^2 + 3} + x)(\sqrt{x^2 + 3} - x)}{\sqrt{x^2 + 3} - x} \).
The numerator becomes a difference of squares: \((\sqrt{x^2 + 3})^2 - x^2 = x^2 + 3 - x^2 = 3\).
Now, the expression simplifies to: \( \frac{3}{\sqrt{x^2 + 3} - x} \).
Analyze the behavior of the denominator as \( x \to -\infty \). Simplify \( \sqrt{x^2 + 3} \approx |x| \) for large \( |x| \), and consider the limit of the simplified expression.

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