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Ch. 2 - Limits and Continuity
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 2, Problema 2.6.25

Limits as x → ∞ or x → −∞


The process by which we determine limits of rational functions applies equally well to ratios containing noninteger or negative powers of x. Divide numerator and denominator by the highest power of x in the denominator and proceed from there. Find the limits in Exercises 23–36. Write ∞ or −∞ where appropriate.


lim x → ⁻∞ ((1 − x³) / (x² + 7x))⁵

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1
Identify the highest power of x in the denominator, which is x² in this case.
Divide both the numerator and the denominator by x², the highest power of x in the denominator.
Rewrite the expression: ((1/x² - x³/x²) / (1 + 7/x))⁵.
Simplify the expression: ((1/x² - x) / (1 + 7/x))⁵.
Evaluate the limit as x approaches -∞. As x → -∞, 1/x² → 0, 7/x → 0, and -x → ∞. Therefore, the expression simplifies to ((0 - ∞) / (1 + 0))⁵, which further simplifies to (-∞)⁵.

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Rational Functions

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