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Ch. 2 - Limits and Continuity
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Non è quello che usi tu?Cambia libro di testo
Capitolo 2, Problema 2.2.48

Limits with trigonometric functions


Find the limits in Exercises 43–50.


limx→0 (1 + x + sin x) / (3 cosx)

Guida verificata passo dopo passo
1
Step 1: Understand the problem. We need to find the limit of the function (1 + x + sin(x)) / (3 cos(x)) as x approaches 0.
Step 2: Apply the limit property that allows us to evaluate the limit of a quotient by finding the limits of the numerator and the denominator separately, provided the limit of the denominator is not zero.
Step 3: Evaluate the limit of the numerator, 1 + x + sin(x), as x approaches 0. Use the fact that sin(x) approaches 0 as x approaches 0, and x approaches 0 as x approaches 0. Therefore, the limit of the numerator is 1 + 0 + 0 = 1.
Step 4: Evaluate the limit of the denominator, 3 cos(x), as x approaches 0. Use the fact that cos(x) approaches 1 as x approaches 0. Therefore, the limit of the denominator is 3 * 1 = 3.
Step 5: Combine the results from Steps 3 and 4 to find the limit of the entire expression. The limit of the quotient is the limit of the numerator divided by the limit of the denominator, which is 1 / 3.

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